The true mean hours of sleep a night of college students in the United States is 6.2 hours. Suppose you want to use a hypothesis test to determine whether the mean hours of sleep a night of BYU-Idaho students is higher than the national mean. Which of the following pairs of hypotheses is the most appropriate for addressing this question?H_o : mu = 6.2 qquad H_a : mu > 6.2 H_o : mu > 6.2 qquad H_a : mu = 6.2 H_o : mu = 6.2 qquad H_a : mu != 6.2 H_o : mu != 6.2 qquad H_a : mu = 6.2 H_o : mu = 6.2 qquad H_a : mu < 6.2 H_o : mu < 6.2 qquad H_a : mu = 6.2

Option A)

Step-by-step explanation:

We are given he following in the question:

Population mean = 6.2 hours.

The hypothesis wants to determine if the mean hours of sleep a night of  students is higher than the national mean.

Thus, we can design the null and alternate hypothesis as:

The null hypothesis states that mean hours of sleep a night of students is equal to the national mean that is 6.2 hours.

The alternate hypothesis states that mean hours of sleep a night of students is higher than the national mean that is 6.2 hours.

Thus, the correct answer is

Option A)

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.