A skateboarder free-fell 26 ft onto a ramp. The distance s(t), in feet, traveled by a body falling freely from rest in t seconds is approximated by s (t )equals 16 t squared. Estimate the skateboarder's velocity at the moment he touched down onto the ramp.

26.14 ft/s

Step-by-step explanation:

Assume that the acceleration was constant throughout the whole fall and equal to the acceleration of gravity which is roughly 32.17 ft/s.

If the distance travelled was 26 ft, the time it took him to land was:

At the apex, just before the fall, the skateboarder velocity is zero. The velocity of an object, initially at rest and accelerating at a constant rate, is:

The skateboarder's velocity at the moment he touched down onto the ramp was 26.14 ft/s.

fwms@lil_ben06

step-by-step explanation:

n=1.75+1.75

step-by-step explanation:

3.5/2=1.75