Two containers, X and Y, are each filled by an ideal gas at the same temperature. The volume of Y is half the volume of X. The number of moles of gas in Y is three times the number of moles of the gas in X. The pressure of the gas in X is PX and the pressure of the gas in Y is PY. What is the ratio LaTeX: \frac{P_X}{P_Y}P Y P Y

The answer to the question is

The ratio of the two gas pressures   , that is Px to Py = 1/6

Step-by-step explanation:

Let the gases Volumes be V₁ and V₂

Where volume of X = V₁ and

volume of Y = V₂

The volume of Y is half the volume of X

∴ V₂  =   × V₁

Let the number of moles be n₁ and n₂ in X and Y respectively

therefore  n₂ = 3 × n₁

The pressure of the gas in X is Pₓ and the pressure of the gas in Y is   then we have

P₁ × V₁  = n₁ × R × T₁ , and P₂ × V₂ = n₂ × R × T₂

(P₁ × V₁)/(n₁ × T₁) = (P₂ × V₂)/(n₂ × T₂)

but T₁ = T₂

Therefore

(P₁ × V₁)/n₁ = (P₂ × V₂)/n₂.  However  n₂ = 3 × n₁  and V₂  =   × V₁ therefore substituting in the equation we have

(P₁ × V₁)/n₁ = (P₂ ×   × V₁ )/(3 × n₁) from where

P₁ /P₂ =  ( × V₁ × n₁)/(V₁×3 × n₁) =0.5/3 = 1/6

The ratio of = 1/6

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)