Y=–6x 2 –12x – 2y=–4 how many solutions does this linear system have?

y = -6x + 2 . . . . . . . . equation (1)

-12x - 2y = -4 . . . . . . equation (2)

substitute  (1) into (2),

-12x - 2(-6x + 2) = -4

-12x + 12x - 4 = -4

-4 = -4

Both sides are same. If we arrive at a statement that is true, then the system has infinite number of solution.

So there are infinite number of solutions for system of equations

y=-6x + 2 and -12x - 2y=-4

step-by-step explanation:

in the absence of parentheses, i will have to make some assumptions:   i interpret your (3x+5/y^6)(4y^3/5)​ to mean:

3x + 5     4y^(3/5)       (3x + 5)(4)

* =

    y^6             1               y^(6-3/5)

if this is not what you expected, repost your question using parentheses to indicate whether you meant

4y^3

    or   4y^(3/5)

    5