Charles drew a regular hexagon and divided it into two identical trapezoid the diagonal shown in 30 is 32 cm Charles measure the height of one the trapezoid and found that the height was 13.9 cm find the area of the

669cm2

Step-by-step explanation:

correct question

Charles drew a regular hexagon and divided it into two identical trapezoid , the side length of the hexagon iscoming16cm,the diagonal shown in fig 30 is 32 cm Charles measure the height of one the trapezoid and found that the height was 13.9 cm find the area of the area

Step-by-step explanation:

The side length of the hexagon should be given which is 16 cm

To get the Length the side lenght makes with the height of the trapezium, Pythagoras theorem is applied to get the base of the triangle

Base = √((16)^2 - (13.9)^2

Base = √62.29

Base = 7.92cm

Since we have gotten the base

Diagonal - the base gives the top length of the trapezium.

32- 7.92- 7.92 = 16.16

The area of the hexagon gives the 2 times of the trapezium.

To find the area of the trapezium

= 1/2 * ( a+b)h

= 1/2* ( 32+ 16.16)* 13.9

= 24.04*13.9

Area of th trapezium = 334.71cm2

= 334.71 * 2

= 669.42cm2

we know that

applying the law of sines

°

so

∠j=18°

∠k=29°

∠l=180-(18+29)=133°

the answer part a) is

the measure of angle k is  ≈29°

part b)  the measure of angle k could also be

(180-29)=151°

so

∠j=18°

∠k=151°

∠l=180-(18+151)=11°

the answer part b) is

the measure of angle k could also be 151°

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