The radius r(t)r(t)r, (, t, )of the base of a cylinder is increasing at a rate of 111 meter per hour and the height h(t)h(t)h, (, t, )of the cylinder is decreasing at a rate of 444 meters per hour. At a certain instant t_0t 0 t, start subscript, 0, end subscript, the base radius is 555 meters and the height is 888 meters. What is the rate of change of the volume V(t)V(t)V, (, t, )of the cylinder at that instant?

The volume is decreasing at a rate 20π cubic meter per hour.

Step-by-step explanation:

We are given the following in the question:

The radius is increasing at a rate 1 meter per hour.

The height is decreasing at a rate 4 meter per hour  

At an instant time t,

r = 5 meter

h = 8 meters

Volume of cylinder =

where r is the radius and h is the height of the cylinder.

Rate of change of volume is given by:

Putting all the values we get,

Thus, the volume is decreasing at a rate 20π cubic meter per hour or 62.8 cubic meter per hour.      

answer: i think the answer is etheir c or d but i don't know which one but have a good day!

step-by-step explanation:

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180