A missile is launched from the ground. It’s height, h(x), can be represented by a quadratic function in terms of time, x, in seconds
After 1 second, the missile is 110 feet in the air; after 2 seconds, it is 200 feet in the air

Step-by-step explanation:

Let

x ----> the time in seconds

f(x) ----> the height in feet

we know that

 The standard form for the quadratic, which is the function that models parabolic motion, is

Remember that

The problem tells us that the missile was launched from the ground, so c (the initial height of the missile) is 0.

so

We have two given points

(1,110) and (2,200)

substitute

----> equation A

----> equation B

Solve the system of equation s by graphing

Remember that the solution is the intersection point both lines

using a graphing tool

The solution is (-10,120)

see the attached figure

therefore

a=, b=

The quadratic equation is

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