Find the average speed of a horse that traveled East for 25 km in 4 hours.
A) 6.25 km/h due East
B) 6.25 km/h
C) 62.5 km/h due East
D) 62.5 km/h

A.6.25km/h due east

Step-by-step explanation:

Speed = distance/time

Distance =25km

Time = 4hrs

Speed = 25/4

=6.25km/h

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

9 x 8 divided by (5-3)=36