(X^4/6y)^-2 (y-2/4x-1)^3

{x,y} = {1/3,1/9}

Step-by-step explanation:

Solution :

{x,y} = {1/3,1/9}  

System of Linear Equations entered :

  [1]    4x + 6y = 2

  [2]    -4x + 3y = -1

Graphic Representation of the Equations :

   6y + 4x = 2        3y - 4x = -1  

Solve by Substitution :

// Solve equation [2] for the variable  y  

 [2]    3y = 4x - 1

 [2]    y = 4x/3 - 1/3

// Plug this in for variable  y  in equation [1]

  [1]    4x + 6•(4x/3-1/3) = 2

  [1]    12x = 4

// Solve equation [1] for the variable  x  

  [1]    12x = 4  

  [1]    x = 1/3  

// By now we know this much :

   x = 1/3

   y = 4x/3-1/3

// Use the  x  value to solve for  y  

   y = (4/3)(1/3)-1/3 = 1/9  

Solution :

{x,y} = {1/3,1/9}

the answer is the third / last answer

step-by-step explanation:

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