How do I graph and shade the inequalities?

y < 2x - 1

y 2 -x + 3

  see below

Step-by-step explanation:

Graph the boundary lines as though these were equations. For the first inequality, which does not include the "or equal to" case,  the line is dashed.

Now, look at y in relation to the comparison symbol. For "y < ...", values of y that are in the solution set will be below (less than) those in the line, so the shading is below the line. For "y ≥ ...", values of y that are in the solution set will be above (greater than) those in the line, so the shading is above the line.

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The graph of y=2x-1 has a slope of 2 and intersects the y-axis at y=-1. The graph of y=-x+3 has a slope of -1 and intersects the y-axis at y=3.

$450

step-by-step explanation:

first, you have to multiply 150x2=300

next, you have to add 150+300= 450

x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17