A frog is climbing out of a well that is 15 feet deep, the frog climbs 4 feet per hour, and then the frog slips back 1 foot while resting for an hour. How long will it take the frog to get out of the well? Do not use algebra for this question!

10 hours

Step-by-step explanation:

Hello! :)

In 2 hours, he is going up 4 feet and down 1 which means he advances 3 feet every two hours.

15 ft/3 ft=5 ft

2 hours x 5 ft=10 more hours

Hope this could help!

The answer to your question is 9 h

Step-by-step explanation:

                                                                  Distance                   Time

- 1 stage   climbs to 4 and slips 1 ft          the frog is 3 ft            2 h

- 2 stage  climbs to 7 and slips 1 ft         the frog is 6 ft           4 h

- 3 stage  climbs to 10 and slips 1 ft         the frog is 9 ft           6 h

- 4 stage climbs to 13 and slips 1 ft        the frog is 12 ft         8 h

- 5 stage climbs out of the well                                                  9 h

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just needed some points but try socratic