Sue has 5 ropes of 5350 mm each. if she ties them together to make one long rope and each kont takes up 15 cm, how long will the rope be

26150 mm

Step-by-step explanation:

Size of each rope = 5350 mm

Number of ropes = 5

Total size of all five ropes = 5 * 5350 = 26750 mm

Number of knots between the ropes = Number of ropes - 1

= 5-1 = 4

Each knot takes up 15 cm of the rope.

So 4 knots will take up (4*15) cm of the rope.

This is equivalent to 60 cm of the rope or 600 mm of the rope.

So the effective length of the combined rope will be (26750-600) mm =  26150 mm

sec ф = 5/3 (quadrant 4)

let x = base

y = perp

z = hypotenuse

sec ф = hypotenuse/base = 5/3

⇒ z = 5 and x = 3

finding y:

z² = x² + y²

5² = 3² + y²

y² = 25-9

y² = 16

y = 4

now finding all other geometric functions of theta:

sin ф = y/z = 4/5

sin ф = -4/5 (sin is negative in the 4th quadrant)

cos ф = x/z = 3/5

cos ф = 3/5 (cos is positive in 4th quadrant)

tan ф = y/x = 4/3

tan ф = -4/3 (tan is negative in 4th quadrant)

cosec ф = z/y = 5/4

cosec ф = -5/4 (cosec is negative in the 4th quadrant)

cot ф = x/y = 3/4

tan ф = -3/4 (tan is negative in 4th quadrant)

its c or d   take a lucky guess my dude