Write an equation of the line that passes through the point
(6,-5) and is parallel to the line whose equation is 2x - 3y = 11

First we have to transform 2x-3y=11 into common form y=ax+b, so
2x-3y=11   /-2x both side
-3y=11-2x    /:(-3) both side
y=
Parallel condition is 
Our , so we are sure that new equation looks
y=
To find b, we can substitute x and y from point (6,-5).
-5=
-5=4+b   /-4 both side
-9=b
So, the result is
y=