Agame designer must decide how to color four buildings that are in a row. using only the colors yellow, green, red, and blue, each building must be painted with exactly one color. any two neighboring buildings must be different colors, and the first and last buildings must be different colors. how many ways are there to paint the four buildings?

The number of ways are there to paint the four buildings is 48.

Step-by-step explanation:

I) let the first building be any color. Therefore the first building can be painted with any of the 4 colors.

Therefore the first building can be colored in 4 ways.

ii) the second building can be colored in 3 ways since it cannot be colored the

same color as the first building.

iii) the third building can also be colored in 3 ways.

iv) the last building can be colored in 2 ways because it cannot be the same color as the first building or the color of the adjacent building.

Therefore the total number of ways the buildings can be colored = 4 3 3   2 = 48.

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.