Asap for brainliest: the time required to finish a test in normally distributed with a mean of 60 minutes and a standard deviation of 10 minutes. what is the z-score for a student who finishes the test in 23 minutes? show work : )

The z-score = -3.7 and p (-3.7) = 0.00011 or 0.011%

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Mean of time to finish a test = 60 minutes

Standard deviation of time to finish a test = 10 minutes

Time that a student finishes the test = 23 minutes

2. What is the z-score for the student?

z-score = (Time that a student finishes the test - Mean of time to finish a test)/Standard deviation of time to finish a test

Replacing with the real values:

z-score = (23 -60)/10 = -37/10 = -3.7

z-score = -3.7 and p (-3.7) = 0.00011 or 0.011%

3x^3-x^2+6x-9

13

step-by-step explanation:

169-1=168

168-3=165

165-5=160

160-7=153

153-9=144

144-11=133

133-13=120

120-15=105

105-17=88

88-19=69

69-21=48

48-23=25

25-25=0

since it took 13times to completely subtract it hence its square root is 13