Asap for brainliest: the time required to finish a test is normally distributed with a mean of 60 minutes and a standard deviation of 10 minutes. what is the z-score for a student who finishes the test in 45 minutes? show work!

the z score is - 1.5

Step-by-step explanation:

Since the time required to finish a test is normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = time required to finish the test

µ = mean time

σ = standard deviation

From the information given,

µ = 60 minutes

σ = 10 minutes

We want to find the z-score for a student who finishes the test in 45 minutes

For x = 45,

z = (45 - 60)/10 = - 15/10 = - 1.5

what is the rest of the question? ?

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation: