Acertain system has two components. there are 6 different models of the first component and 10 different models of the second. any first component can be paired with any second component. a salesman must select 2 of the first component and 3 of the second to take on a sales call. how many different sets of components can the salesman take?

1800

Step-by-step explanation:

Given : A certain system has two components.

Number of different models of the first component = 6

Number of different models of the second component  = 10

A salesman must select 2 of the first component and 3 of the second to take on a sales call , so we use combinations ( ∵ order of selection not matters)

The number of different sets of components can the salesman take =

Hence, the number of different sets of components can the salesman take = 1800

$30.32

step-by-step explanation:

65.00*.12=2.80

65.00-2.80=57.20

57.20*1.06=60.632

60.632/2=30.316

the answer is 21%.