Side a of a triangle is twice the length of side b side c is 4cm longer then side a if the perimeter is 26cm find the length of each side

The length of side A is 8.8 cm and length of side B is 4.4 cm and length of side C is 12.8 cm

Solution:

Let the length of side A be "a"

Let the length of side B be "b"

Let the length of side C be "c"

Side A of a triangle is twice the length of side B

a = 2b

Side C is 4 cm longer then side A

c = 4 + a ------------- eqn 2

The perimeter is 26 cm

The perimeter of triangle is given by formula:

Perimeter = a + b + c

Where, "a", "b", "c" are the length of sides of triangle

Therefore,

26 = a + b + c

Substitute eqn 1 and eqn 2 in above

Substitute a = 8.8 in eqn 1

b = 4.4

Substitute a = 8.8 in eqn 3

c = 4 + 8.8

c = 12.8

Thus length of side A is 8.8 cm and length of side B is 4.4 cm and length of side C is 12.8 cm

answer: procent 54 wynosi 33,33%

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call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

25.45584