Urn 1 contains 2 white and 4 black balls and urn 2 contains 4 white and 4 black balls. if a ball is drawn at random from one of the two urns, what is the probability that it is a white ball?

Step-by-step explanation:

Given : Urn 1 contains 2 white and 4 black balls and urn 2 contains 4 white and 4 black balls.

Total balls in Urn 1 = 6

Total balls in Urn 2 = 8

Probability of drawing white ball from Urn 1 = P(W |Urn 1) =

Probability of drawing white ball from Urn 2 = P(W |Urn 2)=

Then probability that Urn1 is chosen =P(Urn 1)

Similarly , P(Urn 2)

By Law of total probability :

P(White)= P(W |Urn 1) x P(Urn 1) +P(W |Urn 2) x P(Urn 12)

Hence, the probability that it is a white ball =

answer: 42

use a calculator to find that 845/73 = 11.575

the whole part of the answer is 11. multiply this by 73 to get 11*73 = 803.

subtract that result from 845 to get 845 - 803 = 42