Find the solution of the system of equations 3x+4y=10 and x−y=1. give the x value followed by the y value, separated by a comma

the solution is (2, 1)

Step-by-step explanation:

The given system of simultaneous equations is given as

3x+4y=10 - - - - - - - - - - - - -1

x−y=1 - - - - - - - - - - - - 2

We would eliminate x by multiplying equation 1 by 1 an equation 2 by 3. It becomes

3x + 4y = 10

3x - 3y = 3

Subtracting, it becomes

7y = 7

Dividing the left hand side and the right hand side of the equation by 7, it becomes

7y/7 = 7/7

y = 1

Substituting y = 1 into equation 2, it becomes

x - 1 = 1

Adding 1 to the left hand side and the right hand side of the equation, it becomes

x - 1 + 1= 1 + 1

x = 2

muyb ajo

step-by-step explanation:

jegosu

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15