Gabi is working on another backyard project. she is building a fence to keep deer out of her garden. one side of her garden is against a wall, so she only needs to build three sides of the fence. she has 100 feet of fencing. if she needs to enclose a 600 square foot area, what should the length and width of her fence be? xy = 600 2x + y = 100 y = -2x x(-2x + 100) = x x = 600 x2 – 50x = -300 (x – 25)2 = 325 |x – 25| = 5

Both solutions are valid.

Explanation:

1. First assumption is that the shape of the fence is rectangular.

2. Second, assum the length parallel to the wall measure y feet, so the other two lengths, y, together with x will add up 100 feet

3. The, the area of the fence will be:

4. Now you have two equation with two variables which you can solveL

5. Solve the last equation by completing squares:

Both values are valid,

If x = 43 , then y = 600/43 = 14

If x = 7, then y = 600/7 = 86

Thus, the lenght and width of the fence may be:

the entire expression should be subtracted from 30. to subtract the quantity, distribute the negative sign, which changes the signs on the terms. so, the –2 changes to positive and gets added to 30 instead of subtracted from it.

hope this ! ^w^

its a straight line parallel to the time axis