The length of a spring varies directly with the mass of an object that is attached to it. when a 30-gram object is attached, the spring stretches 9 centimeters. which equation relates the mass of the object, m, and the length of the spring, s?

The required equation is

Step-by-step explanation:

Given: The length of a spring varies directly with the mass of an object that is attached to it. When a 30-gram object is attached, the spring stretches 9 centimeters.

To find : Which equation relates the mass of the object, m, and the length of the spring, s?

Solution :

Let the mass of the object  m,

Length of the spring s,

When a 30-gram object is attached, the spring stretches 9 centimeters.

i.e, the times length of the object is attached to spring is

The length of a spring varies directly with the mass of an object that is attached to it.

According to question,

i.e, length of the spring is 3 by 10 times the mass of the object.            

Therefore, The required equation is

b

step-by-step explanation:

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length