Apurse contains $2.45 in dimes and quarter. there are two more than twice as many dimes as quarters. how many of each coin on the purse. (álgebra 1 price per unit problem)

5 quarters 12 dimes

Step-by-step explanation:

The quarters have to be a odd number or you wouldn't have the 5 at the end of the number. Because there are "two more then twice as many" dimes then quarters the number of quarters has to stay down. 3 to 5 is a good guess to start. from there you can add up the dimes until it all fits together

15 batches are the most you can make

step-by-step explanation:

$9.89

step-by-step explanation:

9.90 = p x .06 x .25 (3/12 changed to a decimal)

9.90 = p x 0.015

9.90 - 0.015 = p

9.89 = p