Mathematics, 27.01.2020 22:31 jessicaisbaehood

Astudent solves the equation startfraction x + 3 over 2 endfraction = startfraction 3 x + 5 over 5 endfraction using the steps in the table.
original equation
startfraction x + 3 over 2 endfraction = startfraction 3 x + 5 over 5 endfraction
cross multiplication
5 (x + 3) = 2 (3x + 5)
distributive property
5 x + 15 = 2 (3 x + 5)
subtraction property of equality
5 = x

which method of solving for the variable could be used instead of cross multiplication?
distributing x + 3 and then 3x + 5 to both sides of the equation
distributing x – 3 and then 3x – 5 to both sides of the equation
using the multiplication property of equality to multiply both sides of the equation by 10
using the multiplication property of equality to multiply both sides of the equation by one-tenth

Answers: 2

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Astudent solves the equation startfraction x + 3 over 2 endfraction = startfraction 3 x + 5 over 5 e...

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