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2(2x β 3) = β2 + 2(2x β 2) 2 ( 2 x - 3 ) = - 2 + 2 ( 2 x - 2 )
x = 6 x...
Mathematics, 27.01.2020 20:31 rozalee14
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2(2x β 3) = β2 + 2(2x β 2) 2 ( 2 x - 3 ) = - 2 + 2 ( 2 x - 2 )
x = 6 x = 6
no solutions
x = 26 x = 26
all real numbers
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