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Mathematics, 27.01.2020 20:31 rozalee14

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2(2x βˆ’ 3) = βˆ’2 + 2(2x βˆ’ 2) 2 ( 2 x - 3 ) = - 2 + 2 ( 2 x - 2 )

x = 6 x = 6
no solutions
x = 26 x = 26
all real numbers

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Answers: 2

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2(2x βˆ’ 3) = βˆ’2 + 2(2x βˆ’ 2) 2 ( 2 x - 3 ) = - 2 + 2 ( 2 x - 2 )

x = 6 x...
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