Find the values of x and y that satisfy both equations below.

The answer to your question is  (4/3, -1)

Step-by-step explanation:

Convert both equations to the same base

        27 = 3 x 3 x 3 = 3³  

          9 = 3 x 3 = 3²

Substitution

Simplify

                                      3x - 6 = 2y                         Equation l

            32 = 2 x 2 x 2 x 2 x 2 = 2⁵

             8 = 2 x 2 x 2 = 2³          

                                   2

Simplify

                                  5y - 3 = -6x                            Equation ll

Equal to zero both equations

                                3x - 2y - 6 = 0                         Equation l

                                6x + 5y - 3 = 0                          Equation ll

Solve by elimination

Multiply equation l by 5 and equation ll by 2

                               15x - 10y - 30 = 0

                               12x + 10y - 6 = 0

                                27x        -36 = 0

Solve for x

                                 27x = 36

                                     x = 36 / 27

Simplify                        x = 4/3

Find the y value

                                6(4/3) + 5y - 3 = 0

                                8 + 5y - 3 = 0

                                      5y = -8 + 3

                                      5y = -5

                                        y = -5/5

                                        y = -1

Solution

                                  (4/3, -1)

square root of 36/6 = 2.449489743

square root of 16/6 = 1.632993162

square root of 6 = 2.449489743

the answer is square root of 16/6 because the square root of 36/6 is the same answer as square root of 6 = 2.449489743

a. 32 degrees

step-by-step explanation:

here we have to use the rule.

m∠e = 1/2 (major arc - minor arc)

m∠e = 1/2 (212 - 148)

m∠e = 1/2 (64)

m∠e = 32 degrees

answer: a. 32 degrees

you