Solving by elimination 2s + 3b= 28 3s + 2b =27

s=5 b=6

Step-by-step explanation:

2s + 3b = 28.

3s + 2b = 27

First, multiply the first eqn by 3 and multiply the first eqn by 2.

FROM FIRST EQUATION

3 (2s + 3b= 28)

6s + 9b = 84.

FROM SECOND EQUATION

2 (3s+2b =27)

6s + 4b = 54

FIRST EQUATION - SECOND EQUATION

(6s+9b)-(6s+4b) = 84-54

6s+9b-6s-4b = 30

6s-6s+9b-4b=30

5b=30

b=6

Then, substitute b=6 into the first eqn.( the second eqn also can be used)

6s+9(6) =84

6s + 54 = 84

6s = 84-54

6s = 30

s=5

Thank you.

up

step-by-step explanation:

the orientation of the parabolas can easily be found by analysing the power of x and y and their signs. if x is squared , parabola opens up and also if its coefficient is negative it opens down. if y is squared , the parabola opens right and also if its coefficient is negative it opens left. however in order to do the above analysis our equation must be in standard form .

our parabola is

which is not standard form of any parabola . hence we square on both hand side and convert it into standard form.

hence we see that x is squared and its coefficient is non negative . there for it opens up.

b