Simplify 6x + 3(–2x + 7) + 2x.
a.
2x + 21
b.
14x + 21
c.
–10x + 7
d.
–14x + 7

answer: 21 + 2 x

step-by-step explanation:

simplify the expression.

simplify 6x + 3(–2x + 7) + 2x.

a.2x + 21

let's simplify step-by-step.

6x+3(−2x+7)+2x

distribute:

=6x+(3)(−2x)+(3)(7)+2x

=6x+−6x+21+2x

combine like terms:

=6x+−6x+21+2x

=(6x+−6x+2x)+(21)

=2x+21

step-by-step explanation:

equation

you are asked to write the equation

  expression = 0

using the given expression. when you do that, you have

  2x^2-2x-12 = 0

factoring

you can see that each of the coefficients is even, so a factor of 2 can be removed immediately.

  2(x^2 -x -6) = 0

if you multiply the binomials (x+a)(x+b), you get

  (x +a)(x +b) = x^2 +(a+b)x +ab

this tells you the coefficient of x is the sum of two factors of the constant term. here, that means -1 is the sum of two factors of -6. we want to know those factors so we can factor the trinomial.

  -6 = -1×6 = -2×3 = -3×2 = -6×1

the factor pair that sums to -1 is {-3, 2}, so our factorization is

  2(x -3)(x +2) = 0

solutions

the solutions to this equation are the values of x that make the product zero. a product is zero only when only of the factors of the product is zero. here, that means

  x - 3 = 0

  x = 3 . . . add 3 to both sides of the equation

or

  x +2 = 0

  x = -2 . . . add -2 to both sides of the equation

the solutions to the equation are x=3 or x=-2. both of these values of x satisfy the equation—they make it be true.

"a" determine whether sage found the correct quotient. show your work

step-by-step explanation: