Aball is throw into the air from the top of a building. the height h(t) of the ball above the ground t seconds after it is thrown can be modeled by h (t) =-16t +64t+80 how many seconds after being thrown will the ball hit the ground

The ball will hit the ground 5 seconds after being thrown.

Step-by-step explanation:

The correct function is:

You can rewrite the Quadratic function given in the exercise with making . Then this is:

Now you can simplify the equation dividing both sides by -16. So you get:

To find the solution of the Quadratic equation, you can facfor it. In order to do this, it is necessary to find two numbers whose sum is -4 and whose product is -5. These number would be -5 and 1.

Therefore, you get this result:

Since the time cannot be negative, you can conclude that the ball will hit the ground 5 seconds after being thrown.

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