If f(x) = x^2+ 1 and g(x) = x-4, which value is equivalent to (fxg) (10)?

Sorry, I always get confused whether I have to do this: f(x)g(x) or this: f(g(x))  but I'll do both and I hope one of them looks very familiar

(f × g)(x) = f(x) × g(x)

(f × g)(10) = f(10) × g(10)

Since you know x = 10, substitute/plug in 10 for x in the equations

f(10) = x² + 1 = (10)² + 1 = 100 + 1 = 101

g(10) = x - 4 = (10) - 4 = 6

(f × g)(10) = 101 × 6 = 606

(f × g)(x) = f(g(x))        

(f × g)(10) = f(g(10))     First find g(10), since we already did you can do this:

                                  g(10) = 6        

(f × g)(10) = f(g(10)) = f(6)          Now find f(x) when x = 6

f(6) = (6)² + 1 = 36 + 1 = 37

i think the answer is d im not sure