Ann and bill play rock-paper-scissors. each has a strategy of choosing uniformly at random out of rock, paper, and scissors every round (making independent selections each round). each round can end in a win, loss, or a tie for each player.

a. what is the probability ann wins the first round. (remember that a tie is a possibility)

prob=
b. what is the probability that ann's first win happens in round #5?

prob=
c. what is the probability that ann's first win comes after round #5?

prob=

a) 1/3

b) 0.0658436214  

Step-by-step explanation:

Part a

Ann wins first round = (P , R) + (S , P) + (R , S) = 3 possibilities of win

Total outcomes = Wins + Losses + Ties = 9 possibilities

Hence,

P (Ann wins first round) = 3/9 = 1/3

Part b

Ann losses or ties first 4 rounds and wins 5th round

P(Ann loosing or tie in any round) = 6/9 = 2/3

Hence,

P(Ann wins 5th round only) = (2/3)^4 * (1/3) = 0.0658436214  

Part c

i can you with this answer

step-by-step explanation:

answer:

given the linear inequality :

add 2y to both sides we get;

simplify:

add 12 to both sides of an equation;

simplify:

divide both sides by 2 we get;

or

the related equation for the inequality equation [1] is;

y-intercepts defined as the graph crosses the y-axis.

substitute x =0 in [2] to solve for y;

y = 6

x-intercepts defined as the graph crosses the x-axis.

substitute value y = 0 to solve for x;

subtract 6 from both sides we get

multiply both sides by 2 we get;

or

x = -12

now, plot these point (0, 6) and (-12, 0) on graph as shown below and shade the graph below the solid line.