Suppose that a certain population satisfies the initial value problem dy/dt = r(t)y − k, y(0) = y0, where the growth rate r(t) is given by r(t) = (1 + sin t)/5, and k represents the rate of predation. (a) suppose that k = 1/5. plot y versus t for several values of y0 between 1/2 and 1. (b) estimate the critical initial population yc below which the population will become extinct. (c) choose other values of k and find the corresponding yc for each one. (d) use the data you have found in parts (b) and (c) to plot yc versus k

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~

1,407.5 hours

step-by-step explanation:

we first convert all the time to hours and then sum them up.

there are 24 hours in 1 day, in 58 days, there are 24 x 58 = 1,392 hours.

there are 60 minutes in 1 hour, thus, 30 minutes will be equivalent to 30 / 60 = 0.5 hours.

therefore, the number of hours it will take mercury to complete a full rotation is 1,392 + 15 + 0.5 = 1,407.5 hours

no

explanation:

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i need points

step-by-step explanation: