With a short time remaining in the day, a delivery driver has time to make deliveries at 66 locations among the 99 locations remaining. how many different routes are possible? there are possible different routes. (simplify your answer.)

197,443,926,105,102,399,225,573,693

Step-by-step explanation:

Here we use combination which is the selection of all or part of a set of objects or items without considering the order of selection.

Mathematically, The number of 'r' combinations from 'n' elements is given as :

nCr = n!÷((n-r)!r!)

From the question above :

n=99 r=66

99C66 = 99!÷((99-66)!66!)

99!÷(33!66!) = 197,443,926,105,102,399,225,573,693

There are 197,443,926,105,102,399,225,573,693 different possible routes.

exa:

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3+11

14

step-by-step explanation:

from this example, we can see that subtracting with integers is the same as adding the opposite. we can solve using a number line or by using the saying "keep, change, change" to us solve. it is important to remember that we can subtract a negative and end up with a larger number than we started with.

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v