Adie is thrown twice. let x1 and x2 denote the outcomes, and define random variable x to be the minimum of x1 and x2. determine the distribution of x.

Step-by-step explanation:

Given that a die is thrown twice.  

X1, X2 are the outcomes in 2 throws

X1 = minimum of two

X1 can be either 1 or 2...6

Total outcomes are 36.

For x1 =1, fav ourable outcomes are (1,1) (1,2)...(1,6) (6,1)...(2/,1)= 11

P(X1=1) = \

P(X1=2) =Prob for one die showing two and other die showing 2 to 6

=

P(x1=3) = Prob for one die showing three and other die showing 3 to 6

=

thus we find that probability is reducing by 2 in the numerator

P(x1=4) = 5/36 followed by 3/36 for 5 and 1/36 for 6

idk

step-by-step explanation:

2/3

step-by-step explanation:

the slope of a line is equal to the rise/run. in this case the line rises 2 units for every +3 units it moves