Jose is standing 10 feet east of a mail-box when he begins walking directly east of the mailbox at a constant speed of 6 feet per second. a. how far east is jose from the mail-box 5 seconds after he started walking? b. write a formula that expresses jose's distance from the mailbox (in feet),in terms of the number of seconds t since he started walking. c. as jose walks away from the mail-box, is his distance from the mail-box proportional to the time elapsed since he started walking away from the mailbox?

a). 40 feet

b). 10 + 6t

c). Distance between the mail box and Jose is directly proportional to the time elapsed.

Step-by-step explanation:

Jose is standing 10 feet east of a mail box. If he starts walking with a constant speed 6 feet per second east of the mail box then

a). Distance traveled in 5 seconds with the same speed of 6 feet per second

= (6×5)

= 30 feet

Therefore, distance from the mail box = 10 + 30 = 40 feet

b). In time t distance traveled by Jose = Speed × Time

= 6t meter

Distance between mail box and Jose = (10 + 6t) meter

Formula will be,

c). From the given formula,

We can observe that with the increase in time, Jose distance from the mail box is increasing.

Therefore, S ∝ t.

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