Mathematics, 24.01.2020 23:31 kellersweeney
Suppose the value of x varies from x=2 to x=5.25. how much did the value of x change?
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How many real-number solutions does the equation have? -4x^2 + 10x + 6 = 0 a. no solutions b. two solutions c. infinitely many solutions d. one solution
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Suppose the value of x varies from x=2 to x=5.25. how much did the value of x change?...
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