An amateur photographer wants to set up his camera to view the sunrise coming over the mountain and needs to know the angle to set up his equipment. if they set up their camera 324 meters from the base of the mountain and the mountain is 580 meters high, what angle should he point his camera from the horizontal. round to the hundredths. (2 decimal place)

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understand that i don't know the answers

will someone answer his question

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i used the pitagoras theoreme

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we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v