John is 3 years older than jim. jim is 4 years less than twice david’s age. how old are the three boys if their ages add up to 35?

15  years , 12  years , 8 years.

Step-by-step explanation:

Given:

John is 3 years older than Jim.

Jim is 4 years less than twice David’s age.

Ages of three boys add up to 35.

Question asked:

How old are the three boys?

Solution:

Let age of David =

Let age of Jim =

Then age of John will be =

As Jim is 4 years less than twice David’s age

Equation will be  ,

Multiplying both side  by 2

                       =  (let equation 1 )

As ages of three boys add up to 35.

Equation will be,

                           =

Subtracting both side by 3

                           =  

                          =  (let equation 2 )

subtracting equation 1 and 2,we get

                           =  

                          =  

                          =  

                          =

dividing both side by 5

                              (David ages)

Then  ( age of Jim)  

                                    =

                                    =

Then age of John will be,

                                            =

Thus, age of John = 15 years

Age of Jim = 12 years

Age of David = 8 years

what is the answer?

correct choice is b

step-by-step explanation:

when you calculate the average rate of change of a function, you are finding the slope of the secant line between the two points. for the function the average rate of change from point to point can be calculated as

to find the average rate of change from day 2 to day 10, note that at day 2, 8 houses were sold, so a(2,8) and at day 10, 2 houses were sold, so b(10,2). thus,