Find the volume of the cone if the heights of the solids are equal and the cross sectional areas at every level parallel to the respective bases are also equal. round to the nearest hundredth.

If the heights are equal and the cross-sectional areas are equal, then the volumes are equal. 

for the pyramid:  
at h=0, a = 9ft * 8ft = 72 ft² 
at h = 17ft/2, a = ½ * 9ft * ½ * 8ft = 18 ft² 
at h = 17ft, a = 0. 
then a(h) = 72ft² * (17 - h)²/289 = (72ft²/289)(289 - 34h + h²) 
then v = ∫[a,b] a(h) dh = ∫[0,17] (72ft²/289)(289 - 34h + h²) dh 
v = (72ft²/289)(289h - 17h² + h³/3) |[0,17] 
v = (72ft²/17²)(17³ - 17³ + 17³/3) = 72ft² * 17/3 = 408 ft³ 

(or did you simply know that the volume of a rectangular pyramid is 
v = basearea * height / 3 

The full question isn’t shown. part of it is cut off

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