Liquid product with 10% product solids is blended withsugar before being concentrated (removal of water) to obtaina final product with 15% product solids and 15% sugarsolids. determine the quantity of final product obtainedfrom 200 kg of liquid product. how much sugar is required? compute mass of water removed during con

mass of the water removed =  66.67 kg

Step-by-step explanation:

given data

solids is blended with sugar = 10%

obtain  final product = 15% product

obtain  final product = 15% sugar solids

The initial product is = 200 kg

solution

we get here amount of sugar required that is

amount of sugar required = 200 ×

amount of sugar required =  20 kg

and we know total solid  = product solids +  sugar solids    ...............1

and

initial product =  final product    

so

0.20 ×  200kg= 0.30 ×  mass of the final product

mass of final product = 133.33 kg

but here

final product = 15% product solids and 15% sugar solids

so that amount of product solid = sugar solid

so

mass of the water removed = 200 kg - 133.33 kg

mass of the water removed =  66.67 kg

correct answers below:

the revenue of the fitness center, y, is the product of two factors: the number of members and the fee paid by each member. there are 320 members now, but number of members goes down by 10 for each $5 increase in fees, so if x is the number of $5 price increases then members is equal to (320 - 10x). since the fee is currently $45, and the fee increases by $5 for every price bump x, the fee is given by (45 + 5x). so, revenue y is given by y = (320 - 10x)(45 + 5x).