Show that defg is a rectangle.

in the steps

Step-by-step explanation:

D(-2,3) E(4,-1) F(2,-4) G(-4,0)

slope DG: (0-3)/(-4+2) = -3/-2 = 3/2

slope EF: (-4+1)/(2-4) = -3/-2 = 3/2

DG // EF

slope DE: (-1-3)/(4+2) = -4/6 = -2/3

slope GF: (-4-0)/(2+4) = -4/6 = -2/3

DE // GF

slope DG = - 1/slope DE

DG ⊥ DE

The same reason

DG ⊥ GF

DE ⊥ EF

EF ⊥ GF

∴ DEFG is a parallelogram with four 90° interior angles, it's a rectangle

the answer to the question is a  

it has the same slope and the same y-intercept.

yes   because as the functions are graphed they eventually will intersect unless otherwise

step-by-step explanation: