What is the slope of the line that contains the points (-2,5) and (6-3)

m = -1

Step-by-step explanation: In this problem we're asked to find the slope of the line that contains the points (-2,5) and (6,-3).

Using our slope formula, we take the second y minus the first y which in this case is -3 - 5 over our second x minus our first x which in this case is 6 - -2.

-3 - 5 simplifies to -8 and remember that minus a negative can be thought of as plus a positive so 6 - (-2) can be thought of as 6 + (+2) which is 8.

Now we have -8/8. Notice that our slope can be simplified one step further so we have m = -1.

The variable that's used to represent slope is m.

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

none.

step-by-step explanation:

m

1

=

5

m1=5

b

=

−

1

b=-1

find the slope and y-intercept of the second equation.

tap for more

m

2

=

0

m2=0

b

=

−

6

b=-6

compare the slopes

m

m of the two equations.

m

1

=

5

,

m

2

=

0

m1=5,m2=0

compare the two slopes in the decimal form. if the slopes are equal, then the lines are parallel. if the slopes are not equal, then the lines are not parallel.

m

1

=

5

,

m

2

=

0

m1=5,m2=0