Michael beasley is shooting free throws. making or missing free throws doesn't change the probability that he will make his next one, and he makes his free throws 75%, percent of the time. what is the probability of michael beasley making all of his next 4 free throw attempts?
a. 75^8
b. 375^4
c. 75^4
d. 1.50^2

C.  

Step-by-step explanation:

Let x be the binomial variable that denotes the number of makes.

Since each throw is independent from the other throw , so we can say it follows Binomial distribution .

So

Binomial distribution formula: The probability of getting x success in n trials :

, where p = probability of getting success in each trial.

Then, the probability of Michael Beasley making all of his next 4 free throw attempts will be :

Thus, the probability of Michael Beasley making all of his next 4 free throw attempts is

Hence, the correct answer is C.  .

5 x 14?

im new, sorry if this is wrong.

step-by-step explanation:

may i see the picture? it would a lot, xox