Sandy is upgrading her internet service. fast internet charges $45 for installation and $49.45 per month.
quick internet has free installation but charges $56.95 per month.
part 1 out of 2
complete the equation that can be used to find the number of months after which the internet service
would cost the same. use the variable x to represent the number of months of internet service purchased.
the equation is
+=

x = 6 months.

The equation is given by $45 + ($49.45 × x) = ($56.95 × x).

Step-by-step explanation:

i) Let x be the number of months of Internet Service purchased till the Fast

  Internet charges and Quick Internet charges become the same.

ii) Charges for Fast Internet for x months is given by $45 + ($49.45 × x)

iii) Charges for Quick Internet for x months is given by ($56.95 × x)

iv) According to the first statement we will now equate the equations in ii)  

   and iii) and solve for x.

   Therefore, $45 + ($49.45 × x) = ($56.95 × x)

                      45 + 49.45 x  =  56.95 x

  Therefore  (56.95 - 49.45) x = 45

                    7.50 × x  =  45

  Therefore x = 45 ÷  7.5 = 6

1 is c

2 is a

3 is a

step-by-step explanation: