Best answer gets

find the equation of a line that is perpendicular to line g that contains (p, q).

3x − y = 3p − q
3x + y = q − 3p
x − y = p − q
x + y = q − p

The equation of a perpendicular line g that contains (P,Q) is

3 x-y = 3 P - Q

Step-by-step explanation:

The given points are A(0,5) and B(-3,6) ( In the graph)

slope of the line

The slope of two points formula is  

(1)

substitute the given points are A(0,5) and B(-3,6) in equation(1)

we get[/tex]

Perpendicular condition :-

The two lines are perpendicular then their slopes are

so we know that slope of first line

now we have to find slope of perpendicular line is

so

there fore slope of perpendicular line is

Equation of straight line

The equation of straight line having slope m= 3 and passing through the point (P,Q) is

now

on simplification

Final answer:-

The equation of a line is perpendicular to line g contains (P,Q) is

3 x-y+3 P-Q

for b its (t) and c its (d)

step-by-step explanation: