What are the x-intercepts of this quadratic function? g(x) = -2(x − 4)(x + 1) a. (4,0) and (-1,0) b. (-4,0) and (-1,0) c. (4,0) and (1,0) d. (-4,0) and (1,0)

Option A. (4,0) and (-1,0)

Step-by-step explanation:

we know that

The equation of a vertical parabola in factored form is equal to

where

a is a coefficient

x_1 and x_2 are the zeros or x-intercepts of the function

In this problem we have

we have

The leading coefficient is negative, that means the parabola open downward

The zeros of the function are

Remember that the x-intercepts are the values of x when the value of the function is equal to zero

therefore

The x-intercepts are (4,0) and (-1,0)

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

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