What are the domain and range of the function?

f(x)=−35x3

domain: (−∞, 0)∪ (0, ∞)

range: (−∞, 0)∪ (0, ∞)

domain: (−∞, 0)∪ (0, ∞)

range: (−∞, 0)

domain: (−∞, 0)∪ (0, ∞)

range: (0, ∞)

domain: (−∞, ∞)

range: (−∞, 0)

The domain and the range of the functions is real numbers. Hence, option A is correct.

We need to determine the domain and range of the function  .

Let us define the domain and the range of the function:

Domain:

When all the possible values of an independent variable for which we get the real value of a dependent variable then the values of the independent variables is called domain of the function.

Range:

All the possible values of the function is called the range of the function. Range is the sub-set of co-domain.

Now,

For the given function .

No value of x can restrict the above function hence its domain is real number that is .

And, range of the function is also the same .

Thus, the domain and the range of the functions is real numbers. Hence, option A is correct.

To know more about the domain, please refer to the link:

link

step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

hope this : )

la parábola es el lugar

geométrico en el cual los puntos tienen una distancia idéntica, equidistantes,

de un punto denominado foco, f, y una recta denominada directriz

el radio vector de una

parábola es el segmento que existe entre un punto cualquiera y el foco.

por la ecuación se observa

que la parábola abre hacia la derecha, por lo cual podemos usar las siguientes fórmulas

la ecuación ordinaria de la

parábola es y^2 = 4px, donde p es la longitud desde el vértice de la parábola al

foco.

la fórmula de la directriz

es x + p = 0

resolviendo:

y^2-9x = 0

y^2 = 9x

4p = 9, entonces p = 9/4

entonces el foco tendrá la

coordenada f(9/4,0)

la directriz vendrá

expresada por

x + p = 0

x = -p

x = -9/4

el problema indica que la

ordenada es igual a 6, entonces

(6)^2=9x

x = 36/9

x = 4

entonces el punto al cual

hay que obtener la distancia será p(4,6)

calculando se tendrá: pf = 

pf = 6,25 u

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step-by-step explanation: