Cars a and b are traveling from town x to town y on the same route at constant speeds. car a is initially behind car b, and car a’s speed is 1.25 times car b’s speed. car a passes car b at 1: 30 pm. at 3: 15 pm, car a reaches town y, and at that moment, car b is still 35 miles away from town y. what is the speed of car a?
(a) 60 mph
(b) 75 mph
(c) 80 mph
(d) 96 mph
(e) 100 mph

40 is the final : )

well there are two answers for that.

1: you need 120 ones then that will equal up to 120.

2: you could also do one 100 and 2 tens.

those are the answers that i have thought of.

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

1.true 2.false? ? i think. .

step-by-step explanation: