Write an equation of a line in slope intercept form with slope -3 going through the point (2, -2)

y = - 3x + 4

Step-by-step explanation:

The equation of a line in slope- intercept form is

y= mx + c ( m is the slope and c the y- intercept )

Here m = - 3, thus

y = - 3x + c ← is the partial equation

To find c substitute (2, - 2) into the partial equation

- 2 = - 6 + c ⇒ c = - 2 + 6 = 4

y = - 3x + 4 ← equation of line

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

it has changed from the width and the height.

step-by-step explanation: