Asequence of transformations maps ∆abc to ∆a′b′c′. the sequence of transformations that maps ∆abc to ∆a′b′c′ is a reflection across th

The correct answer is " (1) Reflect ABC across the x-axis and call this new triangle A'B'C'. (2) Translate A'B'C' 2 units right and 6 units up so that its image is A''B''C''. "

It is assumed that the points are
A in ABC is (1,9), B in ABC is (3,12), and C in ABC is (4,4). 

A'' in A''B''C'' is (3,-3), B'' in A''B''C'' is (5,-6), and C'' in A''B''C'' is (6,2).

Both triangles are congruent. Since they are congruent, there are no contractions nor dilations occured. After rotating clockwise, we get A"C"B". So we need to reflect it to get A"B"C"

Maybe fx = lxl because of the way the x is positioned is that what he